What is the extreme f(x,y)=3x-2x^2y+xy^2 ?

The extreme f(x,y)=3x-2x^2y+xy^2 is Saddle(1,1),Saddle(-1,-1)

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extreme f(x,y)=3x-2x^2y+xy^2

extreme points

f (x, y) = 3 x - 2 x^{2} y + x y^{2}

Saddle (1, 1), Saddle (- 1, - 1)

Solution steps

Find the critical points:

(1, 1), (- 1, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2 x

D (x, y) = - 16 x^{2} + 8 x y - 4 y^{2}

Check the sign of at each critical point

Check critical point

(1, 1) :

Saddle

Check critical point

(- 1, - 1) :

Saddle

Saddle (1, 1), Saddle (- 1, - 1)

f (x, y) = \frac{x ^{2} - 2 x y + y}{3 x - 2 y - 6}

f (x) = x^{2} e^{- \frac{1}{x ^{2}}}

f (x) = e^{x^{2} - 8 x - 1} [- 8.8]

f (x) = x^{4} + 6 x^{3} + 12 x^{2} + 8 x + 10

f (x, y) = x^{2} y + x y^{3}

What is the extreme f(x,y)=3x-2x^2y+xy^2 ?
The extreme f(x,y)=3x-2x^2y+xy^2 is Saddle(1,1),Saddle(-1,-1)