What is the extreme f(x)=Y(x)=x^3-3x^2-9x+20 ?

The extreme f(x)=Y(x)=x^3-3x^2-9x+20 is Maximum(-1,25),Minimum(3,-7)

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extreme f(x)=Y(x)=x^3-3x^2-9x+20

extreme points

f (x) = Y (x) = x^{3} - 3 x^{2} - 9 x + 20

Maximum (- 1, 25), Minimum (3, - 7)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 20 : 25

Maximum (- 1, 25)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 20 : - 7

Minimum (3, - 7)

Maximum (- 1, 25), Minimum (3, - 7)

f (x) = - 3 x^{\frac{2}{3}}, - 1 \leq x \leq 1

f (x) = x^{3} + 3 x^{2} - 24 x, - 1 \leq x \leq 3

f (x, y) = x^{2} + x y + y^{2} - 2 x - y

f (x, y) = 6 x y - 4 x^{3} - 3 y^{2}

f (x) = x^{3} - 3 x^{2} + 3 x + 4

What is the extreme f(x)=Y(x)=x^3-3x^2-9x+20 ?
The extreme f(x)=Y(x)=x^3-3x^2-9x+20 is Maximum(-1,25),Minimum(3,-7)