What is the extreme f(x)= 1/3 x^3+1/2 x^2-6x-4 ?

The extreme f(x)= 1/3 x^3+1/2 x^2-6x-4 is Maximum(-3, 19/2),Minimum(2,-34/3)

Popular >

extreme f(x)= 1/3 x^3+1/2 x^2-6x-4

extreme points

f (x) = \frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x - 4

Maximum (- 3, \frac{19}{2}), Minimum (2, - \frac{34}{3})

Solution steps

f^{'} (x) = x^{2} + x - 6

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 3

into

\frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x - 4 : \frac{19}{2}

Maximum (- 3, \frac{19}{2})

Plug

x = 2

into

\frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x - 4 : - \frac{34}{3}

Minimum (2, - \frac{34}{3})

Maximum (- 3, \frac{19}{2}), Minimum (2, - \frac{34}{3})

f (x) = ln (x + 2) + \frac{1}{x}

f (x) = 3 x^{2} + 5 x + 8

f (t) = t 4 - t^{2}

f (x) = y^{3} - x^{2} + 2 y^{2} - 4 x - 3

f (x, y) = 2 x^{3} + x y^{2} + 5 x^{2} + y^{2} + 3

What is the extreme f(x)= 1/3 x^3+1/2 x^2-6x-4 ?
The extreme f(x)= 1/3 x^3+1/2 x^2-6x-4 is Maximum(-3, 19/2),Minimum(2,-34/3)