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Popular >

extreme f(x)=-x^2+x+6

Solution

extreme points

f (x) = - x^{2} + x + 6

Solution

Maximum (\frac{1}{2}, \frac{25}{4})

Solution steps

f^{'} (x) = - 2 x + 1

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- x^{2} + x + 6 : \frac{25}{4}

Maximum (\frac{1}{2}, \frac{25}{4})

Popular Examples

extreme f(x,y)=x^3-y^3+3x^2+3y^2-9x extreme points

f (x, y) = x^{3} - y^{3} + 3 x^{2} + 3 y^{2} - 9 x

extreme (4x)/(x^2-36)extreme points

\frac{4 x}{x ^{2} - 36}

extreme f(x,y)=x^3y^2+5y^2-x+7 extreme points

f (x, y) = x^{3} y^{2} + 5 y^{2} - x + 7

extreme f(x)=x^3-6x^2+12x extreme points

f (x) = x^{3} - 6 x^{2} + 12 x

extreme cos(2φ)extreme points

cos (2 φ)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+x+6 ?
The extreme f(x)=-x^2+x+6 is Maximum(1/2 , 25/4)