What is the extreme f(x)=x^3-6x+5 ?

The extreme f(x)=x^3-6x+5 is Maximum(-sqrt(2),4sqrt(2)+5),Minimum(sqrt(2),-4sqrt(2)+5)

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extreme f(x)=x^3-6x+5

extreme points

f (x) = x^{3} - 6 x + 5

Maximum (- 2, 42 + 5), Minimum (2, - 42 + 5)

Solution steps

f^{'} (x) = 3 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 6 x + 5 : 42 + 5

Maximum (- 2, 42 + 5)

Plug

x = 2

into

x^{3} - 6 x + 5 : - 42 + 5

Minimum (2, - 42 + 5)

Maximum (- 2, 42 + 5), Minimum (2, - 42 + 5)

f (x, y) = y x e^{- (x^{2} + y^{2})}

y = \frac{1}{3} x^{3} + 4

f (x, y) = \frac{1}{x + y}

f (x) = - x^{3} - 3 x^{2} - 3

f (x) = - 4 x + 5

What is the extreme f(x)=x^3-6x+5 ?
The extreme f(x)=x^3-6x+5 is Maximum(-sqrt(2),4sqrt(2)+5),Minimum(sqrt(2),-4sqrt(2)+5)