What is the extreme f(x)=-2x^4+8x^3-1 ?

The extreme f(x)=-2x^4+8x^3-1 is Saddle(0,-1),Maximum(3,53)

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extreme f(x)=-2x^4+8x^3-1

extreme points

f (x) = - 2 x^{4} + 8 x^{3} - 1

Saddle (0, - 1), Maximum (3, 53)

Solution steps

f^{'} (x) = - 8 x^{3} + 24 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 0

into

- 2 x^{4} + 8 x^{3} - 1 : - 1

Saddle (0, - 1)

Plug

x = 3

into

- 2 x^{4} + 8 x^{3} - 1 : 53

Maximum (3, 53)

Saddle (0, - 1), Maximum (3, 53)

f (x, y) = - 3 \cdot x^{2} - 2 \cdot y^{2} + 2 \cdot x \cdot y + 1167 \cdot x + 1479 \cdot y

f (x, y) = x^{2} + y^{2} + ln (x y - 2)

f (x) = 2 x e^{- x}

f (x) = - x^{4} + 50 x^{2} - 625, - 6 \leq x \leq 6

f (x) = \frac{x ^{2}}{x + 2}

What is the extreme f(x)=-2x^4+8x^3-1 ?
The extreme f(x)=-2x^4+8x^3-1 is Saddle(0,-1),Maximum(3,53)