What is the inverse of f(x)=(5-2x)^2 ?

The inverse of f(x)=(5-2x)^2 is -(sqrt(x)-5)/2 ,-(-sqrt(x)-5)/2

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inverse of f(x)=(5-2x)^2

inverse

f (x) = (5 - 2 x)^{2}

- \frac{x - 5}{2}, - \frac{- x - 5}{2}

Solution steps

y = (5 - 2 x)^{2}

Replace

x

with

y

x = (5 - 2 y)^{2}

Solve for

y, x = (5 - 2 y)^{2}

- \frac{x - 5}{2}, - \frac{- x - 5}{2}

- 2 cos (x + 5) - 3

f (x) = \frac{x + 5}{x + 2} + \frac{x + 2}{x + 5}

f (x) = 4 - 7 x^{2}

f (x) = \frac{1}{x ^{2} - 9}

f (x) = 7 x^{4} - 2 x^{3}

What is the inverse of f(x)=(5-2x)^2 ?
The inverse of f(x)=(5-2x)^2 is -(sqrt(x)-5)/2 ,-(-sqrt(x)-5)/2