What is the extreme f(x)=x^3-9x^2+15x+4 ?

The extreme f(x)=x^3-9x^2+15x+4 is Maximum(1,11),Minimum(5,-21)

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extreme f(x)=x^3-9x^2+15x+4

extreme points

f (x) = x^{3} - 9 x^{2} + 15 x + 4

Maximum (1, 11), Minimum (5, - 21)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 15

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 1

into

x^{3} - 9 x^{2} + 15 x + 4 : 11

Maximum (1, 11)

Plug

x = 5

into

x^{3} - 9 x^{2} + 15 x + 4 : - 21

Minimum (5, - 21)

Maximum (1, 11), Minimum (5, - 21)

f (x, y) = Z = x^{2} - 3 x y + 2 y^{2} - 4 y

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 3 y + 10

2 t^{4} + 6 t^{3} - 5

f (x, y) = arcsec (x^{2} - ∣ y ∣)

f (x) = x^{\frac{2}{5}}

What is the extreme f(x)=x^3-9x^2+15x+4 ?
The extreme f(x)=x^3-9x^2+15x+4 is Maximum(1,11),Minimum(5,-21)