What is the extreme f(x)=2x^2-4xy+3y^2-8x+8y-1=0 ?

The extreme f(x)=2x^2-4xy+3y^2-8x+8y-1=0 is None

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extreme f(x)=2x^2-4xy+3y^2-8x+8y-1=0

extreme points

f (x) = 2 x^{2} - 4 x y + 3 y^{2} - 8 x + 8 y - 1 = 0

None

Solution steps

Find the critical points:

None

0

has no critical points, therefore there are no extreme points

None

f (x) = x^{3} + 3 y^{3} + 3 x^{2} + 3 y^{2} + 24

f (x) = \frac{2 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 2 x

f (x) = 9.71 x^{2} + 61.579 x + 943.59

f (x) = 2 x^{3} - 3 x^{2} + 7

x y - x - 3 y

What is the extreme f(x)=2x^2-4xy+3y^2-8x+8y-1=0 ?
The extreme f(x)=2x^2-4xy+3y^2-8x+8y-1=0 is None