What is the extreme 8x^2+14xy+3y^2+10x-4 ?

The extreme 8x^2+14xy+3y^2+10x-4 is Saddle(3/5 ,-7/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme 8x^2+14xy+3y^2+10x-4

extreme points

8 x^{2} + 14 x y + 3 y^{2} + 10 x - 4

Saddle (\frac{3}{5}, - \frac{7}{5})

Solution steps

Find the critical points:

(\frac{3}{5}, - \frac{7}{5})

\frac{\partial ^{2} f}{\partial x ^{2}} = 6

D (x, y) = - 100

Check the sign of at each critical point

Check critical point

(\frac{3}{5}, - \frac{7}{5}) :

Saddle

Saddle (\frac{3}{5}, - \frac{7}{5})

f (x) = 6 x^{2} + 6 x - 12

f (x, y) = x^{3} - 2 x y + y^{2} + 4

f (x) = \frac{x ^{2} + 1}{x ^{2} - 4 x + 4}

f (x, y) = (x - y) (25 - x y)

f (x) = x^{3} - y^{3} - 2 x y + 6

What is the extreme 8x^2+14xy+3y^2+10x-4 ?
The extreme 8x^2+14xy+3y^2+10x-4 is Saddle(3/5 ,-7/5)