What is the extreme f(x,y)= 1/3 x^2+2xy+3y^2+4x-1 ?

The extreme f(x,y)= 1/3 x^2+2xy+3y^2+4x-1 is None

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extreme f(x,y)= 1/3 x^2+2xy+3y^2+4x-1

extreme points

f (x, y) = \frac{1}{3} x^{2} + 2 x y + 3 y^{2} + 4 x - 1

None

Solution steps

Find the critical points:

None

\frac{1}{3} x^{2} + 2 x y + 3 y^{2} + 4 x - 1

has no critical points, therefore there are no extreme points

None

f (x, y) = 4 x + 6 y - x^{2} - y^{2} + 8

f (x) = x^{3} + 6 x^{2} + 8

f (x) = 2 e^{x} - e^{x^{2}}

f (x) = \frac{4 x - 12}{( x - 2 ) ^{2}}

f (x) = \frac{I n x}{x}

What is the extreme f(x,y)= 1/3 x^2+2xy+3y^2+4x-1 ?
The extreme f(x,y)= 1/3 x^2+2xy+3y^2+4x-1 is None