en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3+3x^2+3x-4

Solution

extreme points

f (x) = x^{3} + 3 x^{2} + 3 x - 4

Solution

Saddle (- 1, - 5)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x + 3

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{3} + 3 x^{2} + 3 x - 4 : - 5

Saddle (- 1, - 5)

Popular Examples

extreme y=xsqrt(25-x^2)extreme points

y = x 25 - x^{2}

extreme f(x)=x^6+6/x extreme points

f (x) = x^{6} + \frac{6}{x}

extreme f(x)=8xy-x^3-4y^2 extreme points

f (x) = 8 x y - x^{3} - 4 y^{2}

extreme f(θ)=-5cos(3/4 θ-6)-2 extreme points

f (θ) = - 5 cos (\frac{3}{4} θ - 6) - 2

extreme f(x)=5x+2x^{-1}extreme points

f (x) = 5 x + 2 x^{- 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3+3x^2+3x-4 ?
The extreme f(x)=x^3+3x^2+3x-4 is Saddle(-1,-5)