What is the extreme f(x,y)=2x^3y^2+5/x-1/y+4 ?

The extreme f(x,y)=2x^3y^2+5/x-1/y+4 is

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extreme f(x,y)=2x^3y^2+5/x-1/y+4

extreme points

f (x, y) = 2 x^{3} y^{2} + \frac{5}{x} - \frac{1}{y} + 4

Solution steps

Find the critical points:

\frac{\partial ^{2} f}{\partial x ^{2}} = 4 x^{3} - \frac{2}{y ^{3}}

D (x, y) = - 96 x^{4} y^{2} - \frac{24 x}{y} - \frac{20}{x ^{3} y ^{3}} + 40

Check the sign of at each critical point

Check critical point

Minimum

Check critical point

Maximum

f (x) = \frac{- 7}{x ^{2} - 4}

f (x, y) = x^{2} + y^{2} + x + y + x y

f (x, y) = x^{2} + 2 x + y^{2}

2 x + \frac{72}{x}

f (x) = x^{2} \cdot e^{x}

What is the extreme f(x,y)=2x^3y^2+5/x-1/y+4 ?
The extreme f(x,y)=2x^3y^2+5/x-1/y+4 is