What is the extreme f(x)=3x+9/x ?

The extreme f(x)=3x+9/x is Maximum(-sqrt(3),-6sqrt(3)),Minimum(sqrt(3),6sqrt(3))

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extreme f(x)=3x+9/x

extreme points

f (x) = 3 x + \frac{9}{x}

Maximum (- 3, - 63), Minimum (3, 63)

Solution steps

f^{'} (x) = 3 - \frac{9}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

3 x + \frac{9}{x} : - 63

Maximum (- 3, - 63)

Plug

x = 3

into

3 x + \frac{9}{x} : 63

Minimum (3, 63)

Maximum (- 3, - 63), Minimum (3, 63)

f (x) = x 16 - x^{2}

f (x) = x + 6

- 3 x + 2 y = 20

(1, 5), (1, - 4)

3 x - 4 y + 2

What is the extreme f(x)=3x+9/x ?
The extreme f(x)=3x+9/x is Maximum(-sqrt(3),-6sqrt(3)),Minimum(sqrt(3),6sqrt(3))