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Popular >

extreme f(x)=2x^2+8x

Solution

extreme points

f (x) = 2 x^{2} + 8 x

Solution

Minimum (- 2, - 8)

Solution steps

f^{'} (x) = 4 x + 8

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

2 x^{2} + 8 x : - 8

Minimum (- 2, - 8)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+8x ?
The extreme f(x)=2x^2+8x is Minimum(-2,-8)