What is the extreme f(x)=x^3-6x^2+9x+9 ?

The extreme f(x)=x^3-6x^2+9x+9 is Maximum(1,13),Minimum(3,9)

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extreme f(x)=x^3-6x^2+9x+9

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 9

Maximum (1, 13), Minimum (3, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 9 : 13

Maximum (1, 13)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 9 : 9

Minimum (3, 9)

Maximum (1, 13), Minimum (3, 9)

f (x, y) = 2 x + 4 y - 5

- 2 x^{2} + 4 x + 3

f (x) = \frac{x ^{2}}{( x - 1 )}

f (x) = - x^{3} + 3 x^{2} + 9 x + 10

f (x y) = x^{3} + y^{3} + 3 x^{2} - 3 y^{2} - 8

What is the extreme f(x)=x^3-6x^2+9x+9 ?
The extreme f(x)=x^3-6x^2+9x+9 is Maximum(1,13),Minimum(3,9)