extreme e^{-x}(2x+1)+3

الحلّ

extreme points

e^{- x} (2 x + 1) + 3

عظمى (\frac{1}{2}, \frac{2}{e} + 3)

خطوات الحلّ

f^{'} (x) = - e^{- x} (2 x - 1)

Find intervals:

تصاعديّة

: - \infty < x < \frac{1}{2},

تنازليّة

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

e^{- x} (2 x + 1) + 3 : \frac{2}{e} + 3

عظمى (\frac{1}{2}, \frac{2}{e} + 3)

f (x, y) = 2 x^{4} + 2 y^{4} - 2 x y

x^{3} + \frac{48}{x}

f (x) = 3 x^{5} - 6 x^{3}

f (x, y) = 3 x^{2} + y^{3} - 3 x y

f (x) = x^{3} + x + \frac{4}{x}