What is the extreme 2y^2+2xy+x^2+2y-2x+1 ?

The extreme 2y^2+2xy+x^2+2y-2x+1 is Minimum(-2,3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme 2y^2+2xy+x^2+2y-2x+1

extreme points

2 y^{2} + 2 x y + x^{2} + 2 y - 2 x + 1

Minimum (- 2, 3)

Solution steps

Find the critical points:

(- 2, 3)

\frac{\partial ^{2} f}{\partial y ^{2}} = 2

D (y, x) = 4

Check the sign of at each critical point

Check critical point

(- 2, 3) :

Minimum

Minimum (- 2, 3)

f (x) = x^{2} + y^{4} + 2 x y

(x^{2} - 3) e^{x}

x^{4} + 4 x^{3}

0.07 x^{3} - 1.6 x^{2} + 5.13 x + 5.35

f (x) = x^{3} + 3 x^{2} + b

What is the extreme 2y^2+2xy+x^2+2y-2x+1 ?
The extreme 2y^2+2xy+x^2+2y-2x+1 is Minimum(-2,3)