What is the extreme f(x,y)=ln(x^3y+3xy^3) ?

The extreme f(x,y)=ln(x^3y+3xy^3) is None

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extreme f(x,y)=ln(x^3y+3xy^3)

extreme points

f (x, y) = ln (x^{3} y + 3 x y^{3})

None

Solution steps

Find the critical points:

None

ln (x^{3} y + 3 x y^{3})

has no critical points, therefore there are no extreme points

None

f (x) = 2 x ln (9 x)

f (x, y) = - x^{4} + y^{4} + x^{2} - y^{2}

f (x) = 4 x^{3} + 3 x^{2} - 60 x - 12

f (x) = (x + 5)^{3} + 7

f (x) = \frac{4 x}{x ^{2} - 4}

What is the extreme f(x,y)=ln(x^3y+3xy^3) ?
The extreme f(x,y)=ln(x^3y+3xy^3) is None