What is the extreme f(x)=x^3+6x^2-36x ?

The extreme f(x)=x^3+6x^2-36x is Maximum(-6,216),Minimum(2,-40)

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extreme f(x)=x^3+6x^2-36x

extreme points

f (x) = x^{3} + 6 x^{2} - 36 x

Maximum (- 6, 216), Minimum (2, - 40)

Solution steps

f^{'} (x) = 3 x^{2} + 12 x - 36

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 6

into

x^{3} + 6 x^{2} - 36 x : 216

Maximum (- 6, 216)

Plug

x = 2

into

x^{3} + 6 x^{2} - 36 x : - 40

Minimum (2, - 40)

Maximum (- 6, 216), Minimum (2, - 40)

f (x) = x^{2} + 8 x + 10

16 L W

x + \frac{16}{x}

f (x) = 7 x - 8 y + 2 x y - x^{2} + y^{3}

f (x) = 2 x - 7

What is the extreme f(x)=x^3+6x^2-36x ?
The extreme f(x)=x^3+6x^2-36x is Maximum(-6,216),Minimum(2,-40)