What is the extreme f(x)=2x-4sqrt(x-3) ?

The extreme f(x)=2x-4sqrt(x-3) is Minimum(3,6),Maximum(4,4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x-4sqrt(x-3)

extreme points

f (x) = 2 x - 4 x - 3

Minimum (3, 6), Maximum (4, 4)

Solution steps

f^{'} (x) = 2 - \frac{2}{x - 3}

Find intervals:

Increasing

: 3 \leq x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 3

into

2 x - 4 x - 3 : 6

Minimum (3, 6)

Plug

x = 4

into

2 x - 4 x - 3 : 4

Maximum (4, 4)

Minimum (3, 6), Maximum (4, 4)

f (x) = 2 x^{3} e^{- x}

f (x) = x - 2 sin (x), 0 \leq x \leq 2 π

f (x) = sin (6 x)

f (x) = x^{3} - \frac{3}{2} x^{2} - 6 x

f (x) = x^{\frac{3}{5}}

What is the extreme f(x)=2x-4sqrt(x-3) ?
The extreme f(x)=2x-4sqrt(x-3) is Minimum(3,6),Maximum(4,4)