What is the extreme f(x)=x-2sqrt(x) ?

The extreme f(x)=x-2sqrt(x) is Minimum(0,0),Maximum(1,-1)

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extreme f(x)=x-2sqrt(x)

extreme points

f (x) = x - 2 x

Minimum (0, 0), Maximum (1, - 1)

Solution steps

f^{'} (x) = 1 - \frac{1}{x}

Find intervals:

Increasing

: 0 \leq x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

x - 2 x : 0

Minimum (0, 0)

Plug

x = 1

into

x - 2 x : - 1

Maximum (1, - 1)

Minimum (0, 0), Maximum (1, - 1)

f (x, y) = x^{3} - 3 x + y^{2}

f (x, y) = 2 x^{2} + y^{2} + 3 x y - 3 y - 5 x + 8

4 x^{3} - 3 x^{2} - 6 x + 3

f (x) = - x^{2} + y^{2}

f (x) = 3 x y - x^{2} y - x y^{2}

What is the extreme f(x)=x-2sqrt(x) ?
The extreme f(x)=x-2sqrt(x) is Minimum(0,0),Maximum(1,-1)