What is the extreme f(x)=2x^3+9x^2-24x+5 ?

The extreme f(x)=2x^3+9x^2-24x+5 is Maximum(-4,117),Minimum(1,-8)

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extreme f(x)=2x^3+9x^2-24x+5

extreme points

f (x) = 2 x^{3} + 9 x^{2} - 24 x + 5

Maximum (- 4, 117), Minimum (1, - 8)

Solution steps

f^{'} (x) = 6 x^{2} + 18 x - 24

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 4

into

2 x^{3} + 9 x^{2} - 24 x + 5 : 117

Maximum (- 4, 117)

Plug

x = 1

into

2 x^{3} + 9 x^{2} - 24 x + 5 : - 8

Minimum (1, - 8)

Maximum (- 4, 117), Minimum (1, - 8)

f (x) = x^{2} (x - 4)^{2}

p (x) = e^{x - 3} + e^{- x}

f (x, y) = x^{2} - 2 y + y

f (x, y) = 4 x^{2} + 8 y^{2}

f (x) = \frac{2 x + 1 - 18}{x}

What is the extreme f(x)=2x^3+9x^2-24x+5 ?
The extreme f(x)=2x^3+9x^2-24x+5 is Maximum(-4,117),Minimum(1,-8)