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Popular >

extreme f(x)=x^2-8x+7

Solution

extreme points

f (x) = x^{2} - 8 x + 7

Solution

Minimum (4, - 9)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 7 : - 9

Minimum (4, - 9)

Popular Examples

extreme f(x)=(x-5)/(x^2-6x+9)extreme points

f (x) = \frac{x - 5}{x ^{2} - 6 x + 9}

extreme y=x^3-12x-5 extreme points

y = x^{3} - 12 x - 5

extreme y=x^3-12x+8 extreme points

y = x^{3} - 12 x + 8

extreme (x^2)/(x+3)extreme points

\frac{x ^{2}}{x + 3}

extreme f(x)=sin(4x),0<= x<= pi/2 extreme points

f (x) = sin (4 x), 0 \leq x \leq \frac{π}{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+7 ?
The extreme f(x)=x^2-8x+7 is Minimum(4,-9)