en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme ln(x^4+27)

Solution

extreme points

ln (x^{4} + 27)

Solution

Minimum (0, 3 ln (3))

Solution steps

f^{'} (x) = \frac{4 x ^{3}}{x ^{4} + 27}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{4} + 27) : 3 ln (3)

Minimum (0, 3 ln (3))

Popular Examples

extreme f(x,y)=(2y-x)/((x-1)^2+(y-2)^2)extreme points

f (x, y) = \frac{2 y - x}{( x - 1 ) ^{2} + ( y - 2 ) ^{2}}

extreme f(x,y)=sqrt(x-1)sqrt(y-1)extreme points

f (x, y) = x - 1 y - 1

extreme x(x+2)^3 extreme points

x (x + 2)^{3}

extreme f(x,y)=8x^3+2xy-3x^2+y^2+1 extreme points

f (x, y) = 8 x^{3} + 2 x y - 3 x^{2} + y^{2} + 1

extreme f(x)=3x+4y extreme points

f (x) = 3 x + 4 y

Frequently Asked Questions (FAQ)

What is the extreme ln(x^4+27) ?
The extreme ln(x^4+27) is Minimum(0,3ln(3))