What is the extreme f(x)=x^3-27x+7 ?

The extreme f(x)=x^3-27x+7 is Maximum(-3,61),Minimum(3,-47)

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extreme f(x)=x^3-27x+7

extreme points

f (x) = x^{3} - 27 x + 7

Maximum (- 3, 61), Minimum (3, - 47)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 7 : 61

Maximum (- 3, 61)

Plug

x = 3

into

x^{3} - 27 x + 7 : - 47

Minimum (3, - 47)

Maximum (- 3, 61), Minimum (3, - 47)

f (x) = 2 x^{3} - 9 x^{2} + 7 x + 6

f (x) = \frac{x - 5}{x ^{2}}

f (x) = (x + 1) (x - 1)^{2}

f (x, y) = 3 x^{2} + y^{3} - 3 x y

f (x) = a^{3} y = x^{3} (4 a - 3 x)

What is the extreme f(x)=x^3-27x+7 ?
The extreme f(x)=x^3-27x+7 is Maximum(-3,61),Minimum(3,-47)