What is the extreme f(x)=x^3+3x^2-24x+12 ?

The extreme f(x)=x^3+3x^2-24x+12 is Maximum(-4,92),Minimum(2,-16)

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extreme f(x)=x^3+3x^2-24x+12

extreme points

f (x) = x^{3} + 3 x^{2} - 24 x + 12

Maximum (- 4, 92), Minimum (2, - 16)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 4

into

x^{3} + 3 x^{2} - 24 x + 12 : 92

Maximum (- 4, 92)

Plug

x = 2

into

x^{3} + 3 x^{2} - 24 x + 12 : - 16

Minimum (2, - 16)

Maximum (- 4, 92), Minimum (2, - 16)

f (x, y) = x^{2} - 3 x y + y^{2}

f (x, y) = x^{4} + y^{4} + 3 x^{2} y + 2 x

f (x, y) = x^{2} + y^{2} + 2 x^{2} y^{2}

16

f (x) = - 5 + y - 10 x

What is the extreme f(x)=x^3+3x^2-24x+12 ?
The extreme f(x)=x^3+3x^2-24x+12 is Maximum(-4,92),Minimum(2,-16)