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Popular >

extreme f(x)=x^2-10x+24

Solution

extreme points

f (x) = x^{2} - 10 x + 24

Solution

Minimum (5, - 1)

Solution steps

f^{'} (x) = 2 x - 10

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

x^{2} - 10 x + 24 : - 1

Minimum (5, - 1)

Popular Examples

extreme f(x)=2x+(300000)/x ,1<= x<= 300 extreme points

f (x) = 2 x + \frac{300000}{x}, 1 \leq x \leq 300

extreme f(x)=-(x^2+x)^{2/3}extreme points

f (x) = - (x^{2} + x)^{\frac{2}{3}}

extreme f(x)=-x^4+4x^3 extreme points

f (x) = - x^{4} + 4 x^{3}

extreme 1/3 x^3-x^2+x-5 extreme points

\frac{1}{3} x^{3} - x^{2} + x - 5

extreme f(x)=(x^3)/(x^3+1)extreme points

f (x) = \frac{x ^{3}}{x ^{3} + 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-10x+24 ?
The extreme f(x)=x^2-10x+24 is Minimum(5,-1)