en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-6x^2+12x-5

Solution

extreme points

f (x) = x^{3} - 6 x^{2} + 12 x - 5

Solution

Saddle (2, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 12

Find intervals:

Increasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{3} - 6 x^{2} + 12 x - 5 : 3

Saddle (2, 3)

Popular Examples

extreme f(x,y)=x^4-4x^2+y^4-8y^2+5 extreme points

f (x, y) = x^{4} - 4 x^{2} + y^{4} - 8 y^{2} + 5

extreme f(x)=e^{-6x^2}extreme points

f (x) = e^{- 6 x^{2}}

extreme 2sin(x-pi/6)extreme points

2 sin (x - \frac{π}{6})

extreme f(x)=(2x^2)/(1-x^2)extreme points

f (x) = \frac{2 x ^{2}}{1 - x ^{2}}

extreme f(x,y)=ln(x^2+4y^2-1)extreme points

f (x, y) = ln (x^{2} + 4 y^{2} - 1)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-6x^2+12x-5 ?
The extreme f(x)=x^3-6x^2+12x-5 is Saddle(2,3)