What is the domain of f(x)=sqrt(x^2+5x-6) ?

The domain of f(x)=sqrt(x^2+5x-6) is x = 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x^2+5x-6)

domain

f (x) = x^{2} + 5 x - 6

x \leq - 6 or x \geq 1

Interval Notation

(- \infty, - 6] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 1

The function domain

x \leq - 6 or x \geq 1

\frac{x ^{2} + 3}{x ^{2} - 2 x - 3}

f (x) = - 2 x + 4

f (x) = \frac{7}{x - 3}

f (x) = 2^{- x} - 4

f (x) = 8 x + 2

What is the domain of f(x)=sqrt(x^2+5x-6) ?
The domain of f(x)=sqrt(x^2+5x-6) is x<=-6\lor x>= 1