What is the extreme f(x)=(4x-2)/(x^2-10x+25) ?

The extreme f(x)=(4x-2)/(x^2-10x+25) is Minimum(-4,-2/9)

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extreme f(x)=(4x-2)/(x^2-10x+25)

extreme points

f (x) = \frac{4 x - 2}{x ^{2} - 10 x + 25}

Minimum (- 4, - \frac{2}{9})

Solution steps

f^{'} (x) = - \frac{4 ( x + 4 )}{( x - 5 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - 4

into

\frac{4 x - 2}{x ^{2} - 10 x + 25} : - \frac{2}{9}

Minimum (- 4, - \frac{2}{9})

f (x, y) = x y + 5 x - 5

f (x) = - x^{3} - 6 x^{2}

f (x, y) = x^{2} + 2 x y + 2 y^{2} - x + 2 y

f (x) = x^{3} + 9 x^{2} + 24 x + 20

f (x) = x - \frac{1}{6} x^{2} - \frac{2}{3} ln (x)

What is the extreme f(x)=(4x-2)/(x^2-10x+25) ?
The extreme f(x)=(4x-2)/(x^2-10x+25) is Minimum(-4,-2/9)