What is the extreme f(x)=x^3+9x^2+24x+20 ?

The extreme f(x)=x^3+9x^2+24x+20 is Maximum(-4,4),Minimum(-2,0)

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extreme f(x)=x^3+9x^2+24x+20

extreme points

f (x) = x^{3} + 9 x^{2} + 24 x + 20

Maximum (- 4, 4), Minimum (- 2, 0)

Solution steps

f^{'} (x) = 3 x^{2} + 18 x + 24

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 4

into

x^{3} + 9 x^{2} + 24 x + 20 : 4

Maximum (- 4, 4)

Plug

x = - 2

into

x^{3} + 9 x^{2} + 24 x + 20 : 0

Minimum (- 2, 0)

Maximum (- 4, 4), Minimum (- 2, 0)

f (x) = x - \frac{1}{6} x^{2} - \frac{2}{3} ln (x)

f (x) = e^{x y}

f (x) = \frac{4}{9 - x ^{2} - y ^{2}}

x^{2} + 1

\frac{d}{d x} (I n x (1 - x))

What is the extreme f(x)=x^3+9x^2+24x+20 ?
The extreme f(x)=x^3+9x^2+24x+20 is Maximum(-4,4),Minimum(-2,0)