What is the extreme f(x)=-x^3+3x^2+5 ?

The extreme f(x)=-x^3+3x^2+5 is Minimum(0,5),Maximum(2,9)

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extreme f(x)=-x^3+3x^2+5

extreme points

f (x) = - x^{3} + 3 x^{2} + 5

Minimum (0, 5), Maximum (2, 9)

Solution steps

f^{'} (x) = - 3 x^{2} + 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- x^{3} + 3 x^{2} + 5 : 5

Minimum (0, 5)

Plug

x = 2

into

- x^{3} + 3 x^{2} + 5 : 9

Maximum (2, 9)

Minimum (0, 5), Maximum (2, 9)

x^{5} - 5 x^{3} - 20 x - 2

f (x) = (1 + x y) (x + y)

f (x, y) = x + 4 y

\frac{6 x ^{2}}{x ^{2} - 16}

(\frac{x - 3}{x + 2})^{2}

What is the extreme f(x)=-x^3+3x^2+5 ?
The extreme f(x)=-x^3+3x^2+5 is Minimum(0,5),Maximum(2,9)