What is the extreme f(x)=2x^3+9x^2+1 ?

The extreme f(x)=2x^3+9x^2+1 is Maximum(-3,28),Minimum(0,1)

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extreme f(x)=2x^3+9x^2+1

extreme points

f (x) = 2 x^{3} + 9 x^{2} + 1

Maximum (- 3, 28), Minimum (0, 1)

Solution steps

f^{'} (x) = 6 x^{2} + 18 x

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 3

into

2 x^{3} + 9 x^{2} + 1 : 28

Maximum (- 3, 28)

Plug

x = 0

into

2 x^{3} + 9 x^{2} + 1 : 1

Minimum (0, 1)

Maximum (- 3, 28), Minimum (0, 1)

F (m, a) = m \cdot a

f (x) = x - x^{2}

f (x, y) = - 2 x^{3} - 2 y^{3} + 6 x y + 10

ln (x) + ln (2 - x)

cos^{2} (x) - 2 sin (x)

What is the extreme f(x)=2x^3+9x^2+1 ?
The extreme f(x)=2x^3+9x^2+1 is Maximum(-3,28),Minimum(0,1)