What is the extreme f(x,y)=3x^2-y^2 ?

The extreme f(x,y)=3x^2-y^2 is Saddle(0,0)

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extreme f(x,y)=3x^2-y^2

extreme points

f (x, y) = 3 x^{2} - y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 12

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

3 x^{5} - 5 x^{3} + 1

f (x) = 2 sin (x) - cos (2 x), 0 \leq x \leq 2 π

f (x) = 2 x^{2} + 3 x y + 4 y^{2} - 2 x + 10 y

f (x) = x^{4} - 8 x^{3} - 6

K (r, s) = 3 r - s

What is the extreme f(x,y)=3x^2-y^2 ?
The extreme f(x,y)=3x^2-y^2 is Saddle(0,0)