What is the extreme f(x)= x/(ln(x))at[2.5] ?

The extreme f(x)= x/(ln(x))at[2.5] is None

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extreme f(x)= x/(ln(x))at[2.5]

extreme points

f (x) = \frac{x}{ln ( x )} a t [2.5]

None

Solution steps

Find the critical points:

None

\frac{x}{ln ( x )} a t [2.5]

has no critical points, therefore there are no extreme points

None

f (x) = (x + 5)^{3}

f (x) = x^{6} (1 - x)^{3}

f (x) = 6 x^{2} - 6 x - 12

f (x) = x^{2} + x y + y^{2} - 25 y + 208

f (x, y) = 48 x - 48 y - 6 x^{2} + 6 y^{2}

What is the extreme f(x)= x/(ln(x))at[2.5] ?
The extreme f(x)= x/(ln(x))at[2.5] is None