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Popular >

extreme y=x^2-2x

Solution

extreme points

y = x^{2} - 2 x

Solution

Minimum (1, - 1)

Solution steps

f^{'} (x) = 2 x - 2

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{2} - 2 x : - 1

Minimum (1, - 1)

Graph

Popular Examples

extreme f(x)=2x^3-3x^2-12x+5,0<= x<= 3 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 5, 0 \leq x \leq 3

extreme-x^2+3x-2,1<= x<= 3 extreme points

- x^{2} + 3 x - 2, 1 \leq x \leq 3

extreme (sqrt(2x-x^2))/x extreme points

\frac{2 x - x ^{2}}{x}

extreme f(x)=x^2,-2<= x<= 1 extreme points

f (x) = x^{2}, - 2 \leq x \leq 1

extreme f(x)=(x^2-27)/(x-6)extreme points

f (x) = \frac{x ^{2} - 27}{x - 6}

Frequently Asked Questions (FAQ)

What is the extreme y=x^2-2x ?
The extreme y=x^2-2x is Minimum(1,-1)