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Popular >

extreme f(x)=-x^2+2

Solution

extreme points

f (x) = - x^{2} + 2

Solution

Maximum (0, 2)

Solution steps

f^{'} (x) = - 2 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- x^{2} + 2 : 2

Maximum (0, 2)

Popular Examples

extreme f(x)=-x^2+5 extreme points

f (x) = - x^{2} + 5

extreme f(x)=x^{5/3}-3x^{2/3}extreme points

f (x) = x^{\frac{5}{3}} - 3 x^{\frac{2}{3}}

extreme f(x)=x^3-7x^2-5x+15 extreme points

f (x) = x^{3} - 7 x^{2} - 5 x + 15

extreme f(x)=(-7)/(x^2-1)extreme points

f (x) = \frac{- 7}{x ^{2} - 1}

extreme f(x)=xe^{-8x}extreme points

f (x) = x e^{- 8 x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+2 ?
The extreme f(x)=-x^2+2 is Maximum(0,2)