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Popular >

extreme f(x)=(x^2)/(x^2+7)

Solution

extreme points

f (x) = \frac{x ^{2}}{x ^{2} + 7}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{14 x}{( x ^{2} + 7 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} + 7} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)=(x^2-10x+21)/(2x-15)extreme points

f (x) = \frac{x ^{2} - 10 x + 21}{2 x - 15}

extreme f(x)=-(x^2+2)(x-2)extreme points

f (x) = - (x^{2} + 2) (x - 2)

extreme f(x,y)=x^2-6xy+y^3-3 extreme points

f (x, y) = x^{2} - 6 x y + y^{3} - 3

extreme f(x)=(x+9)^{2/3}extreme points

f (x) = (x + 9)^{\frac{2}{3}}

extreme-x^2+10x-21 extreme points

- x^{2} + 10 x - 21

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2)/(x^2+7) ?
The extreme f(x)=(x^2)/(x^2+7) is Minimum(0,0)