What is the extreme f(x,y)=x^2-2xy ?

The extreme f(x,y)=x^2-2xy is Saddle(0,0)

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extreme f(x,y)=x^2-2xy

extreme points

f (x, y) = x^{2} - 2 x y

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

y = x^{2} + x + 1

x^{3} + 6 x^{2} + 9 x + 1

f (x) = x (\frac{x}{2} - 5)^{4}

f (x) = 1 + 80 x^{3} + 5 x^{4} - 2 x^{5}

f (x) = 18 x y - x^{3} - 9 y^{2}