What is the inverse of f(x)=((x-4))/((x-2)) ?

The inverse of f(x)=((x-4))/((x-2)) is (-4+2x)/(x-1)

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inverse of f(x)=((x-4))/((x-2))

inverse

f (x) = \frac{( x - 4 )}{( x - 2 )}

\frac{- 4 + 2 x}{x - 1}

Solution steps

y = \frac{x - 4}{x - 2}

Replace

x

with

y

x = \frac{y - 4}{y - 2}

Solve for

y, x = \frac{y - 4}{y - 2}

\frac{- 4 + 2 x}{x - 1}

cos (4 x)

x^{2} - 7

ln (x + 3)

\frac{2 x - 7}{x + 3}

f (x) = \frac{5 x ^{2} - 6 x + 8}{6 x ^{7} + 7 x + 15}

What is the inverse of f(x)=((x-4))/((x-2)) ?
The inverse of f(x)=((x-4))/((x-2)) is (-4+2x)/(x-1)