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Popular >

extreme f(x)=4x^2-16x+16

Solution

extreme points

f (x) = 4 x^{2} - 16 x + 16

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = 8 x - 16

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

4 x^{2} - 16 x + 16 : 0

Minimum (2, 0)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-16x+16 ?
The extreme f(x)=4x^2-16x+16 is Minimum(2,0)