What is the extreme f(r,s)=(2r)/(r^4+7s) ?

The extreme f(r,s)=(2r)/(r^4+7s) is None

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extreme f(r,s)=(2r)/(r^4+7s)

extreme points

f (r, s) = \frac{2 r}{r ^{4} + 7 s}

None

Solution steps

Find the critical points:

None

\frac{2 r}{r ^{4} + 7 s}

has no critical points, therefore there are no extreme points

None

f (x) = 1 + \frac{7}{x} - \frac{2}{x ^{2}}

f (x) = x^{\frac{1}{3}} (x + 3)^{\frac{2}{3}}

f (x, y) = x^{2} y + 2 x y^{2} - 2 x y

f (x) = x^{4} - 8 x^{2} + 8

f (x) = 6 x^{4} + 2 x^{3} - 12 x^{2} + 3

What is the extreme f(r,s)=(2r)/(r^4+7s) ?
The extreme f(r,s)=(2r)/(r^4+7s) is None