What is the line (0,-1.45),(180,1.45) ?

The line (0,-1.45),(180,1.45) is y=0.01611…x-1.45

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line (0,-1.45),(180,1.45)

line

(0, - 1.45), (180, 1.45)

y = 0.01611 \dots x - 1.45

Solution steps

Find the line

y = mx + b

passing through

(0, - 1.45)

(180, 1.45)

Compute the slope

(0, - 1.45), (180, 1.45) : m = 0.01611 \dots

Compute the

y

intercept:

b = - 1.45

Construct the line equation

y = mx + b

where

m = 0.01611 \dots

and

b = - 1.45

y = 0.01611 \dots x - 1.45

\frac{3}{x + 1} + 2

f (x) = \frac{5 x}{4 x - 5}

ln (x + 1)

x - 3 + x^{2} - 16

(- 5, 4), (0, - 2)

What is the line (0,-1.45),(180,1.45) ?
The line (0,-1.45),(180,1.45) is y=0.01611…x-1.45