What is the extreme f(x)= 1/3 x^3-x^2+x-2 ?

The extreme f(x)= 1/3 x^3-x^2+x-2 is Saddle(1,-5/3)

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extreme f(x)= 1/3 x^3-x^2+x-2

extreme points

f (x) = \frac{1}{3} x^{3} - x^{2} + x - 2

Saddle (1, - \frac{5}{3})

Solution steps

f^{'} (x) = x^{2} - 2 x + 1

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

\frac{1}{3} x^{3} - x^{2} + x - 2 : - \frac{5}{3}

Saddle (1, - \frac{5}{3})

f (x) = (5 - x) (x + 1)^{2}

f (x, y) = 4 x^{2} - 12 x + y^{2} + 2 y - 10

x^{4} - 8 x^{2} + 1

f (x, y) = \frac{9}{3} x^{2} y + y^{3} - 2 x y^{2}

f (x) = 1 + \frac{1}{x} + \frac{1}{x ^{2}}

What is the extreme f(x)= 1/3 x^3-x^2+x-2 ?
The extreme f(x)= 1/3 x^3-x^2+x-2 is Saddle(1,-5/3)