What is the extreme f(x)=-0.3x^2+42x+200 ?

The extreme f(x)=-0.3x^2+42x+200 is Maximum(70,1670)

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extreme f(x)=-0.3x^2+42x+200

extreme points

f (x) = - 0.3 x^{2} + 42 x + 200

Maximum (70, 1670)

Solution steps

f^{'} (x) = - 0.6 x + 42

Find intervals:

Increasing

: - \infty < x < 70,

Decreasing

: 70 < x < \infty

Plug

x = 70

into

- 0.3 x^{2} + 42 x + 200 : 1670

Maximum (70, 1670)

y = x (x - 4)^{3}

f (x, y) = x^{4} + 6 y - 10

f (x) = (x - 2)^{3}

f (x) = \frac{5 x}{x ^{2} - 4}

f (x, y) = x^{2} + y^{2} + 2 x

What is the extreme f(x)=-0.3x^2+42x+200 ?
The extreme f(x)=-0.3x^2+42x+200 is Maximum(70,1670)