What is the extreme f(x,y)=2x^2-8x+y^2+16y+100 ?

The extreme f(x,y)=2x^2-8x+y^2+16y+100 is Minimum(2,-8)

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extreme f(x,y)=2x^2-8x+y^2+16y+100

extreme points

f (x, y) = 2 x^{2} - 8 x + y^{2} + 16 y + 100

Minimum (2, - 8)

Solution steps

Find the critical points:

(2, - 8)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 8

Check the sign of at each critical point

Check critical point

(2, - 8) :

Minimum

Minimum (2, - 8)

g (x, y) = 32 x + ln (y) + 4 x^{2} y

f (x) = \frac{3 - x ^{2}}{x}

f (x) = 3 e^{\frac{x}{2}} - (x + 1) x + 1

f (x) = \frac{e ^{x}}{9 + e ^{x}}

6 x y - 1.2 x^{2} - 3 y^{4}

What is the extreme f(x,y)=2x^2-8x+y^2+16y+100 ?
The extreme f(x,y)=2x^2-8x+y^2+16y+100 is Minimum(2,-8)