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Popular >

extreme f(x)=-x^2+12x-32

Solution

extreme points

f (x) = - x^{2} + 12 x - 32

Solution

Maximum (6, 4)

Solution steps

f^{'} (x) = - 2 x + 12

Find intervals:

Increasing

: - \infty < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 6

into

- x^{2} + 12 x - 32 : 4

Maximum (6, 4)

Popular Examples

extreme f(x)=3x^2-12x+5,0<= x<= 3 extreme points

f (x) = 3 x^{2} - 12 x + 5, 0 \leq x \leq 3

extreme f(x)=x-sin(x),0<= x<= 2pi extreme points

f (x) = x - sin (x), 0 \leq x \leq 2 π

extreme f(x)=4x^2+y^2-4 extreme points

f (x) = 4 x^{2} + y^{2} - 4

extreme y=x^2-2x-8 extreme points

y = x^{2} - 2 x - 8

extreme f(x,y)=5^2x^4+5^2y^4-4xy+14 extreme points

f (x, y) = 5^{2} x^{4} + 5^{2} y^{4} - 4 x y + 14

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+12x-32 ?
The extreme f(x)=-x^2+12x-32 is Maximum(6,4)