What is the extreme f(x)=x^3+3x^2+5 ?

The extreme f(x)=x^3+3x^2+5 is Maximum(-2,9),Minimum(0,5)

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extreme f(x)=x^3+3x^2+5

extreme points

f (x) = x^{3} + 3 x^{2} + 5

Maximum (- 2, 9), Minimum (0, 5)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} + 5 : 9

Maximum (- 2, 9)

Plug

x = 0

into

x^{3} + 3 x^{2} + 5 : 5

Minimum (0, 5)

Maximum (- 2, 9), Minimum (0, 5)

f (x) = e^{5 x}

f (x, y) = 2 x^{2} - 4 x + y^{2} - 6 y + 3

f (x) = x^{3} + 2, - 1 \leq x \leq 2

f (x) = x x - 5

f (x) = 2 x^{4} - 24 x^{3} + 20

What is the extreme f(x)=x^3+3x^2+5 ?
The extreme f(x)=x^3+3x^2+5 is Maximum(-2,9),Minimum(0,5)