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Popular >

extreme f(x)=(4x)/(x^2-49)

Solution

extreme points

f (x) = \frac{4 x}{x ^{2} - 49}

Solution

None

Solution steps

f^{'} (x) = \frac{4 ( - x ^{2} - 49 )}{( x ^{2} - 49 ) ^{2}}

Find intervals:

None

None

Popular Examples

extreme f(x)=x^3-6x^2+8,-1<= x<= 6 extreme points

f (x) = x^{3} - 6 x^{2} + 8, - 1 \leq x \leq 6

extreme f(x,y)=x^2-xy+y^2+5 extreme points

f (x, y) = x^{2} - x y + y^{2} + 5

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f (x, y) = x^{2} - x y + y^{2} + 6

extreme (x^2-2x-3)/(x^2)extreme points

\frac{x ^{2} - 2 x - 3}{x ^{2}}

extreme f(x)=(-4t^2+50t+16)/((t^2+4)^2)extreme points

f (x) = \frac{- 4 t ^{2} + 50 t + 16}{( t ^{2} + 4 ) ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(4x)/(x^2-49) ?
The extreme f(x)=(4x)/(x^2-49) is None